What is the sum from n=0 to infinity of (3/4)^2 ?

The sum from n=0 to infinity of (3/4)^2 is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (3/4)^2

n = 0 \sum \infty (\frac{3}{4})^{2}

diverges

Solution steps

n = 0 \sum \infty (\frac{3}{4})^{2}

Every infinite sum of a non-zero constant diverges

= diverges

\int (x - 3)^{2} d x

\int 7 tan^{3} (x) d x

1300 + 14 x - 0.1 x^{2} + 0.0005 x^{3}

\int \frac{3 x}{25 x ^{4} - 4} d x

\int \frac{7 x + 1}{x ^{2} - 18 x - 40} d x

What is the sum from n=0 to infinity of (3/4)^2 ?
The sum from n=0 to infinity of (3/4)^2 is diverges