What is implicit 2x^2+xy+2y^2=5 ?

The answer to implicit 2x^2+xy+2y^2=5 is (dy)/(dx)=(-4x-y)/(x+4y)

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implicit 2x^2+xy+2y^2=5

implicit derivative

2 x^{2} + x y + 2 y^{2} = 5

\frac{d y}{d x} = \frac{- 4 x - y}{x + 4 y}

Solution steps

2 x^{2} + x y + 2 y^{2} = 5

Treat

y

y (x)

Differentiate both sides:

4 x + y + x \frac{d y}{d x} + 4 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- 4 x - y}{x + 4 y}

\frac{d y}{d x} = \frac{- 4 x - y}{x + 4 y}

\frac{d}{d t} (e^{6 t s i n (2 t)})

\frac{d}{d x} ((2^{x})^{8})

f (t) = 2 t

2 x^{5} - 3 e^{6 x}

\frac{\partial}{\partial x} (ln (3 x + 3 c t))

What is implicit 2x^2+xy+2y^2=5 ?
The answer to implicit 2x^2+xy+2y^2=5 is (dy)/(dx)=(-4x-y)/(x+4y)