What is the solution for x^2y^'-xy-x^3sin(x)=0 ?

The solution for x^2y^'-xy-x^3sin(x)=0 is y=-cos(x)x+c_{1}x

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x^2y^'-xy-x^3sin(x)=0

x^{2} y^{^{'}} - x y - x^{3} sin (x) = 0

y = - cos (x) x + c_{1} x

Solution steps

x^{2} y^{'} (x) - x y - x^{3} sin (x) = 0

Solve linear ODE:

y = - cos (x) x + c_{1} x

y = - cos (x) x + c_{1} x

\frac{d}{d x} (\frac{3 π}{4 x ^{5}})

\int \frac{12}{1 - cos ( 6 x )} d x

x^{3} + y^{3} = 126

\frac{d}{d x} (3 x^{2} (2 x + 1)^{5})

n = 1 \sum \infty (\frac{n}{n + 5})^{n}

What is the solution for x^2y^'-xy-x^3sin(x)=0 ?
The solution for x^2y^'-xy-x^3sin(x)=0 is y=-cos(x)x+c_{1}x