What is the integral of tan(x)sin(x) ?

The integral of tan(x)sin(x) is ln|tan(x)+sec(x)|-sin(x)+C

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integral of tan(x)sin(x)

\int tan (x) sin (x) d x

ln ∣ tan (x) + sec (x) ∣ - sin (x) + C

Solution steps

\int tan (x) sin (x) d x

Rewrite using trig identities

= \int \frac{1 - cos ^{2} ( x )}{cos ( x )} d x

Expand

\frac{1 - cos ^{2} ( x )}{cos ( x )} : \frac{1}{cos ( x )} - cos (x)

= \int \frac{1}{cos ( x )} - cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{cos ( x )} d x - \int cos (x) d x

\int \frac{1}{cos ( x )} d x = ln ∣ tan (x) + sec (x) ∣

\int cos (x) d x = sin (x)

= ln ∣ tan (x) + sec (x) ∣ - sin (x)

Add a constant to the solution

= ln ∣ tan (x) + sec (x) ∣ - sin (x) + C

\int \frac{( 4 x )}{x ^{2} + 3} d x

x + 2, \frac{1}{x + 1}, x = 2, x = 0

6 e^{x} + \frac{2}{3 x}

\int (2 + tan (\frac{x}{2})) sec^{2} (\frac{x}{2}) d x

f (x) = \frac{x}{x ^{2} - 3}

What is the integral of tan(x)sin(x) ?
The integral of tan(x)sin(x) is ln|tan(x)+sec(x)|-sin(x)+C