What is the derivative of 2x^2-5x ?

The derivative of 2x^2-5x is 4x-5

What is the first derivative of 2x^2-5x ?

The first derivative of 2x^2-5x is 4x-5

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derivative of

2 x^{2} - 5 x

4 x - 5

Solution steps

\frac{d}{d x} (2 x^{2} - 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (5 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5 x) = 5

= 4 x - 5

\frac{d}{d x} ((5 x^{6} + 2 x^{3})^{4})

\frac{d}{d x} (3 x sin (y) + ln (y^{2}))

x \to 3 - lim (x - 3)

\frac{\partial}{\partial x} (y ln (x z^{2}))

\int \frac{1}{( 1 - x ) ^{6}} d x

What is the derivative of 2x^2-5x ?
The derivative of 2x^2-5x is 4x-5
What is the first derivative of 2x^2-5x ?
The first derivative of 2x^2-5x is 4x-5