What is (\partial}{\partial t}(\frac{s-3r)/t) ?

The answer to (\partial}{\partial t}(\frac{s-3r)/t) is -(s-3r)/(t^2)

Popular >

(\partial}{\partial t}(\frac{s-3r)/t)

\frac{\partial}{\partial t} (\frac{s - 3 r}{t})

- \frac{s - 3 r}{t ^{2}}

Solution steps

\frac{\partial}{\partial t} (\frac{s - 3 r}{t})

Treat

s, r

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (s - 3 r) \frac{\partial}{\partial t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= (s - 3 r) \frac{\partial}{\partial t} (t^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= (s - 3 r) (- 1 \cdot t^{- 1 - 1})

Simplify

(s - 3 r) (- 1 \cdot t^{- 1 - 1}) : - \frac{s - 3 r}{t ^{2}}

= - \frac{s - 3 r}{t ^{2}}

x \to 0 lim (3^{\frac{1}{x}})

\frac{\partial}{\partial x} (sinh (x^{2} y))

x^{2} + 3, 4 x^{2}

y^{^{''}} - y = x

\frac{2 x ^{\frac{3}{2}} - x ^{2} + 4}{x}, at x = 4

What is (\partial}{\partial t}(\frac{s-3r)/t) ?
The answer to (\partial}{\partial t}(\frac{s-3r)/t) is -(s-3r)/(t^2)