What is the integral of 1/(sqrt(x-3)) ?

The integral of 1/(sqrt(x-3)) is 2sqrt(x-3)+C

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integral of 1/(sqrt(x-3))

\int \frac{1}{x - 3} d x

2 x - 3 + C

Solution steps

\int \frac{1}{x - 3} d x

Apply u-substitution

: \int 2 d u

= \int 2 d u

Integral of a constant:

\int a d x = a x

= 2 u

Substitute back

u = x - 3

= 2 x - 3

Add a constant to the solution

= 2 x - 3 + C

y = 12 - x, y = x, y = 1

\frac{\partial}{\partial x} (ln (x + 2 y))

e^{t} cos (6 t)

\int_{- 3}^{1} 2 e^{x} d x

x \to \infty lim (0.7 x^{2})

What is the integral of 1/(sqrt(x-3)) ?
The integral of 1/(sqrt(x-3)) is 2sqrt(x-3)+C