What is (\partial)/(\partial x)(3y^2+x^2) ?

The answer to (\partial)/(\partial x)(3y^2+x^2) is 2x

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(\partial)/(\partial x)(3y^2+x^2)

\frac{\partial}{\partial x} (3 y^{2} + x^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (3 y^{2} + x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 y^{2}) + \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (3 y^{2}) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

= 0 + 2 x

Simplify

= 2 x

\int x (2 x + 1)^{7} d x

\frac{d y}{d x} = x (4 - y)

\int x^{2} + 2 x d x

\frac{d}{d x} (\frac{1}{( x + 4 ) ^{2}})

\frac{d}{d x} (sin (2) x)

What is (\partial)/(\partial x)(3y^2+x^2) ?
The answer to (\partial)/(\partial x)(3y^2+x^2) is 2x