What is the solution for (dy)/(dt)-3y=te^{2t} ?

The solution for (dy)/(dt)-3y=te^{2t} is y=-e^{2t}t-e^{2t}+c_{1}e^{3t}

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(dy)/(dt)-3y=te^{2t}

\frac{d y}{d t} - 3 y = t e^{2 t}

y = - e^{2 t} t - e^{2 t} + c_{1} e^{3 t}

Solution steps

\frac{d y}{d t} - 3 y = t e^{2 t}

Solve linear ODE:

y = - e^{2 t} t - e^{2 t} + c_{1} e^{3 t}

y = - e^{2 t} t - e^{2 t} + c_{1} e^{3 t}

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\frac{\partial}{\partial y} (x^{yz})

\frac{\partial}{\partial x} (ln (9 x^{2} + 4 y^{2} + 5))

\frac{\partial}{\partial y} (x^{3} - 2 x y + 15)

\int x arcsec (2 x) d x

What is the solution for (dy)/(dt)-3y=te^{2t} ?
The solution for (dy)/(dt)-3y=te^{2t} is y=-e^{2t}t-e^{2t}+c_{1}e^{3t}