What is the integral from a to x of 1/(b-a) ?

The integral from a to x of 1/(b-a) is (x-a)/(b-a)

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integral from a to x of 1/(b-a)

\int_{a}^{x} \frac{1}{b - a} d x

\frac{x - a}{b - a}

Solution steps

\int_{a}^{x} \frac{1}{b - a} d x

Integral of a constant:

\int a d x = a x

= [\frac{1}{b - a} x]_{a}^{x}

Multiply

\frac{1}{b - a} x : \frac{x}{b - a}

= [\frac{x}{b - a}]_{a}^{x}

Compute the boundaries:

\frac{x}{b - a} - \frac{a}{b - a}

= \frac{x}{b - a} - \frac{a}{b - a}

Simplify

= \frac{x - a}{b - a}

\frac{x ^{2} + 1}{∣ x ∣ - 1}

\frac{d}{d x} (\frac{cos ( 2 x ) + x ^{3}}{tan ( 2 x ) - 3 x})

y^{^{'}} + 4 y = 5 x

\frac{d}{d x} (- \frac{4 x}{( x ^{2} - 1 ) ^{2}})

\frac{d}{d x} (x^{2} - x - 6)

What is the integral from a to x of 1/(b-a) ?
The integral from a to x of 1/(b-a) is (x-a)/(b-a)