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Popular >

f^'(x)=x^2-5

Solution

f^{^{'}} (x) = x^{2} - 5

Solution

f (x) = \frac{x ^{3}}{3} - 5 x + c_{1}

Solution steps

f^{'} (x) = x^{2} - 5

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int x^{2} - 5 d x

\int x^{2} - 5 d x = \frac{x ^{3}}{3} - 5 x + c_{1}

f (x) = \frac{x ^{3}}{3} - 5 x + c_{1}

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\int \frac{1}{3 x ^{2} + 6 x + 78} d x

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\int e^{4 x} cos (7 x) d x

(\partial)/(\partial x)(2/(xz-z^4+x^2))

\frac{\partial}{\partial x} (\frac{2}{x z - z ^{4} + x ^{2}})

t^2(dy)/(dt)+y=0,y(6)=-3,t>0

t^{2} \frac{d y}{d t} + y = 0, y (6) = - 3, t > 0

Frequently Asked Questions (FAQ)

What is the solution for f^'(x)=x^2-5 ?
The solution for f^'(x)=x^2-5 is f(x)=(x^3)/3-5x+c_{1}