What is the tangent of f(x)=x^4,(-2,16) ?

The tangent of f(x)=x^4,(-2,16) is y=-32x-48

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tangent of f(x)=x^4,(-2,16)

tangent of

f (x) = x^{4}, (- 2, 16)

y = - 32 x - 48

Solution steps

Find the slope of

f (x) = x^{4} : \frac{df ( x )}{d x} = 4 x^{3}

Compute the slope of

f (x) = x^{4}

(- 2, 16) : m = - 32

Find the line with slope m=

- 32

and passing through

(- 2, 16) : y = - 32 x - 48

y = - 32 x - 48

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What is the tangent of f(x)=x^4,(-2,16) ?
The tangent of f(x)=x^4,(-2,16) is y=-32x-48