What is the derivative of 1+9x^4 ?

The derivative of 1+9x^4 is 36x^3

What is the first derivative of 1+9x^4 ?

The first derivative of 1+9x^4 is 36x^3

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\frac{d}{d x} (1 + 9 x^{4})

36 x^{3}

Solution steps

\frac{d}{d x} (1 + 9 x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (9 x^{4})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (9 x^{4}) = 36 x^{3}

= 0 + 36 x^{3}

Simplify

= 36 x^{3}

\frac{d}{d x} (x^{3} - \frac{1}{x ^{7}})

\frac{d y}{d x} - e^{x + y} = 0

x \to \infty lim ((\frac{( 4 + x )}{x})^{3 + \frac{x}{3}})

x^{2} - 1 x y + x \frac{d y}{d x} = 0

\int ln ∣ x - 2 ∣ d x

What is the derivative of 1+9x^4 ?
The derivative of 1+9x^4 is 36x^3
What is the first derivative of 1+9x^4 ?
The first derivative of 1+9x^4 is 36x^3