What is the integral from 4 to 9 of (3sqrt(x)) ?

The integral from 4 to 9 of (3sqrt(x)) is 38

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integral from 4 to 9 of (3sqrt(x))

\int_{4}^{9} (3 x) d x

38

Solution steps

\int_{4}^{9} 3 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{4}^{9} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{4}^{9}

= 3 [\frac{2}{3} x^{\frac{3}{2}}]_{4}^{9}

Compute the boundaries:

\frac{38}{3}

= 3 \cdot \frac{38}{3}

Simplify

= 38

y = x^{2} + 2

x \to \infty lim (\frac{x ^{2}}{e ^{x^{3}}})

\frac{d}{d x} (17 cos (x))

x \to - 2 lim (\frac{x ^{2} + 5}{x + 2})

F (T) = \frac{7}{5}

What is the integral from 4 to 9 of (3sqrt(x)) ?
The integral from 4 to 9 of (3sqrt(x)) is 38