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Popular >

du=-e^{-z}dz

Solution

d u = - e^{- z} d z

Solution

z (u) = - ln (u - c_{1})

Solution steps

d u = - e^{- z (u)} d z (u)

Solve separable ODE:

z (u) = - ln (u - c_{1})

z (u) = - ln (u - c_{1})

Popular Examples

limit as x approaches 0-of 1/(3x)

x \to 0 - lim (\frac{1}{3 x})

(\partial)/(\partial x)(x/(xy)+y/(xy))

\frac{\partial}{\partial x} (\frac{x}{x y} + \frac{y}{x y})

integral of (sin^3(x))/(sqrt(cos(x)))

\int \frac{sin ^{3} ( x )}{cos ( x )} d x

x^2y^'+4/3 xy=3cos(3x)y^{-1/2}

x^{2} y^{^{'}} + \frac{4}{3} x y = 3 cos (3 x) y^{- \frac{1}{2}}

area y=sqrt(3x),x=3,y=1 area

y = 3 x, x = 3, y = 1

Frequently Asked Questions (FAQ)

What is the solution for du=-e^{-z}dz ?
The solution for du=-e^{-z}dz is z(u)=-ln(u-c_{1})