What is the integral of e^{r^2} ?

The integral of e^{r^2} is (sqrt(pi))/2 \erfi(r)+C

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integral of e^{r^2}

\int e^{r^{2}} d r

\frac{π}{2} erfi (r) + C

Solution steps

\int e^{r^{2}} d r

Use the nonelementary integral:

\int e^{r^{2}} d r = \frac{π}{2} erfi (r)

= \frac{π}{2} erfi (r)

Add a constant to the solution

= \frac{π}{2} erfi (r) + C

x \to 0 lim (\frac{ln ( 1 )}{x})

\int (x^{7} - 2 x^{6})^{5} (7 x^{6} - 12 x^{5}) d x

n = 1 \sum \infty n e^{- 8 n}

tan^{4} (x)

\frac{\partial}{\partial x} ((2 + 3 x) (3 - 2 x))

What is the integral of e^{r^2} ?
The integral of e^{r^2} is (sqrt(pi))/2 \erfi(r)+C