What is the first derivative of 2-4x ?

The first derivative of 2-4x is -4

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derivative of 2-4x

\frac{d}{d x} (2 - 4 x)

- 4

Solution steps

\frac{d}{d x} (2 - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) - \frac{d}{d x} (4 x)

\frac{d}{d x} (2) = 0

\frac{d}{d x} (4 x) = 4

= 0 - 4

Simplify

= - 4

\int \frac{1}{4 x ^{2} + 2} d x

y^{^{''}} + 6 y^{^{'}} + 25 y = 0, y (0) = 2, y^{^{'}} (0) = - 10

\frac{d}{d x} (\frac{6 x}{1 + 3 x ^{2}})

x \to 0 lim (\frac{1}{x} ln (1 + x))

\int_{0}^{π} t^{2} e^{- s t} d t