What is (\partial)/(\partial x)(x+sin(y+z)) ?

The answer to (\partial)/(\partial x)(x+sin(y+z)) is 1

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(\partial)/(\partial x)(x+sin(y+z))

\frac{\partial}{\partial x} (x + sin (y + z))

1

Solution steps

\frac{\partial}{\partial x} (x + sin (y + z))

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (sin (y + z))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (sin (y + z)) = 0

= 1 + 0

Simplify

= 1

5 + 2 x - 7 x^{3}

\frac{d}{d x} (\frac{1}{2 x ^{2}} + \frac{x ^{4}}{16})

\frac{d}{d x} ((x^{2} - x + \frac{3}{4} x^{4})^{2})

y^{^{'}} = \frac{6 x ^{2} + y ^{2}}{x y}

\int y e^{x y} d x

What is (\partial)/(\partial x)(x+sin(y+z)) ?
The answer to (\partial)/(\partial x)(x+sin(y+z)) is 1