What is the tangent of f(x)=5sqrt(x),\at x=16 ?

The tangent of f(x)=5sqrt(x),\at x=16 is y= 5/8 x+10

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tangent of f(x)=5sqrt(x),\at x=16

tangent of

f (x) = 5 x, at x = 16

y = \frac{5}{8} x + 10

Solution steps

Find the tangent point:

(16, 20)

Find the slope of

f (x) = 5 x : \frac{df ( x )}{d x} = \frac{5}{2 x}

Compute the slope of

f (x) = 5 x

x = 16 : m = \frac{5}{8}

Find the line with slope m=

\frac{5}{8}

and passing through

(16, 20) : y = \frac{5}{8} x + 10

y = \frac{5}{8} x + 10

y^{^{''}} + 2 y^{^{'}} + y = 2 e^{- t}

\frac{x + 2}{x - 1}

\frac{d y}{d x} = \frac{cos ( 5 x )}{e ^{5 y}}

\int \frac{2 e ^{2 x}}{1 + e ^{2 x}} d x

y \frac{d y}{d x} = 2 x (64 + y^{2})

What is the tangent of f(x)=5sqrt(x),\at x=16 ?
The tangent of f(x)=5sqrt(x),\at x=16 is y= 5/8 x+10