What is the derivative of-(3x/y) ?

The derivative of-(3x/y) is -(3(y-x\frac{dy)/(dx))}{y^2}

What is the first derivative of-(3x/y) ?

The first derivative of-(3x/y) is -(3(y-x\frac{dy)/(dx))}{y^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- \frac{3 x}{y})

- \frac{3 ( y - x \frac{d y}{d x} )}{y ^{2}}

Solution steps

\frac{d}{d x} (- \frac{3 x}{y})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (\frac{x}{y})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 3 \cdot \frac{\frac{d x}{d x} y - \frac{d y}{d x} x}{y ^{2}}

\frac{d x}{d x} = 1

= - 3 \cdot \frac{1 \cdot y - \frac{d y}{d x} x}{y ^{2}}

Simplify

- 3 \cdot \frac{1 \cdot y - \frac{d y}{d x} x}{y ^{2}} : - \frac{3 ( y - x \frac{d y}{d x} )}{y ^{2}}

= - \frac{3 ( y - x \frac{d y}{d x} )}{y ^{2}}

x \to - 2 + lim (\frac{x}{x ^{2} - 4})

3 x^{2} + 4 x + 1

\frac{d}{d x} (\frac{x}{2 x - 1})

\frac{d y}{d t} = - 4 y

\int 100 x d x

What is the derivative of-(3x/y) ?
The derivative of-(3x/y) is -(3(y-x\frac{dy)/(dx))}{y^2}
What is the first derivative of-(3x/y) ?
The first derivative of-(3x/y) is -(3(y-x\frac{dy)/(dx))}{y^2}