What is the limit as x approaches 2 of (x^3-8)/(x-4) ?

The limit as x approaches 2 of (x^3-8)/(x-4) is 0

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limit as x approaches 2 of (x^3-8)/(x-4)

x \to 2 lim (\frac{x ^{3} - 8}{x - 4})

0

Solution steps

x \to 2 lim (\frac{x ^{3} - 8}{x - 4})

Plug in the value

x = 2

= \frac{2 ^{3} - 8}{2 - 4}

Simplify

\frac{2 ^{3} - 8}{2 - 4} : 0

= 0

x \to 6 lim (\frac{4}{x - 6})

\frac{d ^{2}}{d x ^{2}} (tan (2 x))

f (x) = \frac{( 2 x ^{2} - 3 x + 1 ) ^{2}}{4} + 2

n = 1 \sum \infty (- x)^{n + 1}

9 ln (5 - 8 x^{2})

What is the limit as x approaches 2 of (x^3-8)/(x-4) ?
The limit as x approaches 2 of (x^3-8)/(x-4) is 0