What is the derivative of 1/(4x^2+3x) ?

The derivative of 1/(4x^2+3x) is -(8x+3)/((4x^2+3x)^2)

What is the first derivative of 1/(4x^2+3x) ?

The first derivative of 1/(4x^2+3x) is -(8x+3)/((4x^2+3x)^2)

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derivative of

\frac{1}{4 x ^{2} + 3 x}

- \frac{8 x + 3}{( 4 x ^{2} + 3 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{4 x ^{2} + 3 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((4 x^{2} + 3 x)^{- 1})

Apply the chain rule:

- \frac{1}{( 4 x ^{2} + 3 x ) ^{2}} \frac{d}{d x} (4 x^{2} + 3 x)

= - \frac{1}{( 4 x ^{2} + 3 x ) ^{2}} \frac{d}{d x} (4 x^{2} + 3 x)

\frac{d}{d x} (4 x^{2} + 3 x) = 8 x + 3

= - \frac{1}{( 4 x ^{2} + 3 x ) ^{2}} (8 x + 3)

Simplify

- \frac{1}{( 4 x ^{2} + 3 x ) ^{2}} (8 x + 3) : - \frac{8 x + 3}{( 4 x ^{2} + 3 x ) ^{2}}

= - \frac{8 x + 3}{( 4 x ^{2} + 3 x ) ^{2}}

\int 36 e^{4 x} 3 + e^{4 x} d x

\frac{d}{d y} (arctan (y))

sin (x) y^{^{'}} = y + 2 x

\int (cos (x) + \frac{1}{9} x) d x

x \to 1 lim (\frac{2 - 7 x}{x + 6})

What is the derivative of 1/(4x^2+3x) ?
The derivative of 1/(4x^2+3x) is -(8x+3)/((4x^2+3x)^2)
What is the first derivative of 1/(4x^2+3x) ?
The first derivative of 1/(4x^2+3x) is -(8x+3)/((4x^2+3x)^2)