What is the solution for y^{''}+4y^'+5y=35e^{-4x},y(0)=-2,y^'(0)=1 ?

The solution for y^{''}+4y^'+5y=35e^{-4x},y(0)=-2,y^'(0)=1 is y=e^{-2x}(-9cos(x)+11sin(x))+7e^{-4x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+4y^'+5y=35e^{-4x},y(0)=-2,y^'(0)=1

y^{^{''}} + 4 y^{^{'}} + 5 y = 35 e^{- 4 x}, y (0) = - 2, y^{^{'}} (0) = 1

y = e^{- 2 x} (- 9 cos (x) + 11 sin (x)) + 7 e^{- 4 x}

Solution steps

y^{''} (x) + 4 y^{'} (x) + 5 y = 35 e^{- 4 x}

Solve linear ODE:

y = e^{- 2 x} (- 9 cos (x) + 11 sin (x)) + 7 e^{- 4 x}

y = e^{- 2 x} (- 9 cos (x) + 11 sin (x)) + 7 e^{- 4 x}

x \to 0 lim ((1 + x^{2}) - 1)

\frac{d}{d x} (cos^{2} (x) sin (x))

(x^{3} + 5) e x

\int \frac{x ^{4}}{x + 4} d x

\frac{\partial}{\partial z} (\frac{e ^{x z + y}}{z ^{2} + w})

What is the solution for y^{''}+4y^'+5y=35e^{-4x},y(0)=-2,y^'(0)=1 ?
The solution for y^{''}+4y^'+5y=35e^{-4x},y(0)=-2,y^'(0)=1 is y=e^{-2x}(-9cos(x)+11sin(x))+7e^{-4x}