What is (\partial)/(\partial s)(t-2s) ?

The answer to (\partial)/(\partial s)(t-2s) is -2

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(\partial)/(\partial s)(t-2s)

\frac{\partial}{\partial s} (t - 2 s)

- 2

Solution steps

\frac{\partial}{\partial s} (t - 2 s)

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial s} (t) - \frac{\partial}{\partial s} (2 s)

\frac{\partial}{\partial s} (t) = 0

\frac{\partial}{\partial s} (2 s) = 2

= 0 - 2

Simplify

= - 2

\int \frac{x + 5}{( x + 4 ) ( x ^{2} - 1 )} d x

\int 25 - x^{2} (2 x) d x

\frac{\partial}{\partial x} (\frac{- t ^{2}}{( 1 - x ^{2} )})

y^{^{'}} - 2 y = x + 5

x \to \frac{5 π}{2} - lim (sec (x))

What is (\partial)/(\partial s)(t-2s) ?
The answer to (\partial)/(\partial s)(t-2s) is -2