What is the integral from 9 to 16 of sqrt(x) ?

The integral from 9 to 16 of sqrt(x) is 74/3

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integral from 9 to 16 of sqrt(x)

\int_{9}^{16} x d x

\frac{74}{3}

Decimal Notation

24.66666 \dots

Solution steps

\int_{9}^{16} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{9}^{16}

= [\frac{2}{3} x^{\frac{3}{2}}]_{9}^{16}

Compute the boundaries:

\frac{74}{3}

= \frac{74}{3}

\frac{d}{d x} (sin (\frac{π x}{8}))

n = 0 \sum \infty \frac{1}{n ( ln ( n ) )}

f (x) = sin (x) + \frac{2}{3} cot (x)

\int \frac{x}{( x + 2 )} d x

y^{^{''}} + 121 y^{^{'}} = cos (10 t)

What is the integral from 9 to 16 of sqrt(x) ?
The integral from 9 to 16 of sqrt(x) is 74/3