What is the integral of 6x*e^{x^2-2} ?

The integral of 6x*e^{x^2-2} is 3e^{x^2-2}+C

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integral of 6x*e^{x^2-2}

\int 6 x \cdot e^{x^{2} - 2} d x

3 e^{x^{2} - 2} + C

Solution steps

\int 6 x e^{x^{2} - 2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int x e^{x^{2} - 2} d x

Apply u-substitution

: \int \frac{e ^{u}}{2} d u

= 6 \cdot \int \frac{e ^{u}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \frac{1}{2} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 6 \cdot \frac{1}{2} e^{u}

Substitute back

u = x^{2} - 2

= 6 \cdot \frac{1}{2} e^{x^{2} - 2}

Simplify

6 \cdot \frac{1}{2} e^{x^{2} - 2} : 3 e^{x^{2} - 2}

= 3 e^{x^{2} - 2}

Add a constant to the solution

= 3 e^{x^{2} - 2} + C

\frac{d}{d z} (sin (z))

\int \frac{1}{- u ^{2} + b - a} d u

x \to \infty lim (\frac{x - x x}{2 x ^{\frac{3}{2}} + 3 x - 5})

9 x + 10

x \to 0 + lim ((x)^{4 x})

What is the integral of 6x*e^{x^2-2} ?
The integral of 6x*e^{x^2-2} is 3e^{x^2-2}+C