What is the derivative of f(x)=-2x-1 ?

The derivative of f(x)=-2x-1 is -2

What is the first derivative of f(x)=-2x-1 ?

The first derivative of f(x)=-2x-1 is -2

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derivative of

f (x) = - 2 x - 1

- 2

Solution steps

\frac{d}{d x} (- 2 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x) - \frac{d}{d x} (1)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= - 2 - 0

Simplify

= - 2

4 x^{2} 25 - x^{2}

n = 1 \sum \infty \frac{6}{( 3 n + 1 ) ^{2}}

y^{^{''}} = e^{x}

\int_{0}^{16} x x d x

f (x) = ln (x^{2} - 4 x + 1)

What is the derivative of f(x)=-2x-1 ?
The derivative of f(x)=-2x-1 is -2
What is the first derivative of f(x)=-2x-1 ?
The first derivative of f(x)=-2x-1 is -2