What is area 3cos(2x),3-3cos(2x) ?

The answer to area 3cos(2x),3-3cos(2x) is 3sqrt(3)+2pi

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area 3cos(2x),3-3cos(2x)

area

3 cos (2 x), 3 - 3 cos (2 x)

33 + 2 π

Decimal Notation

11.47933 \dots

Solution steps

Apply the area formula:

\int_{\frac{π}{6}}^{\frac{5 π}{6}} ∣ 3 cos (2 x) - (3 - 3 cos (2 x)) ∣ d x

Solve

\int_{\frac{π}{6}}^{\frac{5 π}{6}} ∣ 3 cos (2 x) - (3 - 3 cos (2 x)) ∣ d x : 33 + 2 π

The area is:

= 33 + 2 π

x^{2} \cdot y^{^{'}} + (2 - y) = 0

\frac{\partial}{\partial x} ((2 x + 3 y)^{10})

\frac{d}{d x} (e^{x} \cdot sin (x))

x \to 0 lim (2 x^{2} - x)

\int cos^{11} (x) sin (x) d x

What is area 3cos(2x),3-3cos(2x) ?
The answer to area 3cos(2x),3-3cos(2x) is 3sqrt(3)+2pi