What is inverse oflaplace 2(1/(s-3)) ?

The answer to inverse oflaplace 2(1/(s-3)) is 2e^{3t}

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inverse oflaplace 2(1/(s-3))

inverse laplace

2 (\frac{1}{s - 3})

2 e^{3 t}

Solution steps

L^{- 1} {2 (\frac{1}{s - 3})}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 2 L^{- 1} {\frac{1}{s - 3}}

L^{- 1} {\frac{1}{s - 3}} : e^{3 t}

= 2 e^{3 t}

\int e^{2 y} cos (3 y) d y

\frac{\partial}{\partial x} (3 x cos (x) cos (y))

x - 6

\int \frac{x ^{4}}{5 - x ^{5}} d x

\frac{\partial}{\partial x} (y ln (y^{2} - 2 x))

What is inverse oflaplace 2(1/(s-3)) ?
The answer to inverse oflaplace 2(1/(s-3)) is 2e^{3t}