What is the derivative of 3/8 pir^3 ?

The derivative of 3/8 pir^3 is (9pir^2)/8

What is the first derivative of 3/8 pir^3 ?

The first derivative of 3/8 pir^3 is (9pir^2)/8

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derivative of

\frac{3}{8} π r^{3}

\frac{9 π r ^{2}}{8}

Solution steps

\frac{d}{d r} (\frac{3}{8} π r^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{3}{8} π \frac{d}{d r} (r^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{3}{8} π 3 r^{3 - 1}

Simplify

\frac{3}{8} π 3 r^{3 - 1} : \frac{9 π r ^{2}}{8}

= \frac{9 π r ^{2}}{8}

x \to 0 lim (8 csc (x) - \frac{8}{x})

n = 0 \sum \infty 1^{- n}

\int (3 x) d x

\int_{0}^{1} arcsin (y) d y

f (x) = x^{4} - 25 x^{2} + 144, at x = - 1

What is the derivative of 3/8 pir^3 ?
The derivative of 3/8 pir^3 is (9pir^2)/8
What is the first derivative of 3/8 pir^3 ?
The first derivative of 3/8 pir^3 is (9pir^2)/8