What is (\partial)/(\partial x)(2e^x-4xe^y) ?

The answer to (\partial)/(\partial x)(2e^x-4xe^y) is 2e^x-4e^y

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(\partial)/(\partial x)(2e^x-4xe^y)

\frac{\partial}{\partial x} (2 e^{x} - 4 x e^{y})

2 e^{x} - 4 e^{y}

Solution steps

\frac{\partial}{\partial x} (2 e^{x} - 4 x e^{y})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 e^{x}) - \frac{\partial}{\partial x} (4 x e^{y})

\frac{\partial}{\partial x} (2 e^{x}) = 2 e^{x}

\frac{\partial}{\partial x} (4 x e^{y}) = 4 e^{y}

= 2 e^{x} - 4 e^{y}

\int sec^{2} (x t a) n^{6} x d x

\frac{\partial}{\partial x} (y^{2} - x^{3})

\frac{d}{d x} (ln (3 + x - x^{3}))

\int x x - 6 d x

\frac{d}{d x} (x sinh (x) - 8 cosh (x))

What is (\partial)/(\partial x)(2e^x-4xe^y) ?
The answer to (\partial)/(\partial x)(2e^x-4xe^y) is 2e^x-4e^y