What is the derivative of y=sec^2(3x) ?

The derivative of y=sec^2(3x) is 6sec^2(3x)tan(3x)

What is the first derivative of y=sec^2(3x) ?

The first derivative of y=sec^2(3x) is 6sec^2(3x)tan(3x)

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derivative of

y = sec^{2} (3 x)

6 sec^{2} (3 x) tan (3 x)

Solution steps

\frac{d}{d x} (sec^{2} (3 x))

Apply the chain rule:

2 sec (3 x) \frac{d}{d x} (sec (3 x))

= 2 sec (3 x) \frac{d}{d x} (sec (3 x))

\frac{d}{d x} (sec (3 x)) = sec (3 x) tan (3 x) \cdot 3

= 2 sec (3 x) sec (3 x) tan (3 x) \cdot 3

Simplify

2 sec (3 x) sec (3 x) tan (3 x) \cdot 3 : 6 sec^{2} (3 x) tan (3 x)

= 6 sec^{2} (3 x) tan (3 x)

\frac{d}{d y} (2 y - \frac{1}{x} + cos (3 x))

\int (x \cdot cos (5 x)) d x

e^{\frac{1}{x}} 0

x \to + 0 lim (\frac{2 ^{x} - 3 ^{x}}{x})

What is the derivative of y=sec^2(3x) ?
The derivative of y=sec^2(3x) is 6sec^2(3x)tan(3x)
What is the first derivative of y=sec^2(3x) ?
The first derivative of y=sec^2(3x) is 6sec^2(3x)tan(3x)