What is the tangent of f(x)=tan(x),\at x=pi ?

The tangent of f(x)=tan(x),\at x=pi is y=x-pi

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tangent of f(x)=tan(x),\at x=pi

tangent of

f (x) = tan (x), at x = π

y = x - π

Solution steps

Find the tangent point:

(π, 0)

Find the slope of

f (x) = tan (x) : \frac{df ( x )}{d x} = sec^{2} (x)

Compute the slope of

f (x) = tan (x)

x = π : m = 1

Find the line with slope m=

1

and passing through

(π, 0) : y = x - π

y = x - π

\frac{d}{d x} (3^{2})

\int (\frac{5 x ^{3}}{2 x ^{2}}) d x

n = 0 \sum \infty \frac{1}{n + 8}

3 x^{3} - 5 x^{2} + 5 x - 14

d y = \frac{b - y}{a} d x

What is the tangent of f(x)=tan(x),\at x=pi ?
The tangent of f(x)=tan(x),\at x=pi is y=x-pi