What is (\partial)/(\partial y)((xz)/(x^2+y^2)) ?

The answer to (\partial)/(\partial y)((xz)/(x^2+y^2)) is -(2xzy)/((x^2+y^2)^2)

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(\partial)/(\partial y)((xz)/(x^2+y^2))

\frac{\partial}{\partial y} (\frac{x z}{x ^{2} + y ^{2}})

- \frac{2 x zy}{( x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{x z}{x ^{2} + y ^{2}})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x z \frac{\partial}{\partial y} (\frac{1}{x ^{2} + y ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= x z \frac{\partial}{\partial y} ((x^{2} + y^{2})^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} + y ^{2} ) ^{2}} \frac{\partial}{\partial y} (x^{2} + y^{2})

= - \frac{1}{( x ^{2} + y ^{2} ) ^{2}} \frac{\partial}{\partial y} (x^{2} + y^{2})

\frac{\partial}{\partial y} (x^{2} + y^{2}) = 2 y

= x z (- \frac{1}{( x ^{2} + y ^{2} ) ^{2}} \cdot 2 y)

Simplify

x z (- \frac{1}{( x ^{2} + y ^{2} ) ^{2}} \cdot 2 y) : - \frac{2 x zy}{( x ^{2} + y ^{2} ) ^{2}}

= - \frac{2 x zy}{( x ^{2} + y ^{2} ) ^{2}}

\frac{7}{( s - 1 ) ^{3}}

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x \to + 2 lim (\frac{7 x + 4}{3 x + 9})

\int cos^{2} (2 (x + 4)) d x

What is (\partial)/(\partial y)((xz)/(x^2+y^2)) ?
The answer to (\partial)/(\partial y)((xz)/(x^2+y^2)) is -(2xzy)/((x^2+y^2)^2)