What is (\partial)/(\partial x)(((x-y))/((z-y))) ?

The answer to (\partial)/(\partial x)(((x-y))/((z-y))) is 1/(z-y)

Popular >

(\partial)/(\partial x)(((x-y))/((z-y)))

\frac{\partial}{\partial x} (\frac{( x - y )}{( z - y )})

\frac{1}{z - y}

Solution steps

\frac{\partial}{\partial x} (\frac{( x - y )}{( z - y )})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{z - y} \frac{\partial}{\partial x} (x - y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{z - y} (\frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (y))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= \frac{1}{z - y} (1 - 0)

Simplify

= \frac{1}{z - y}

y = \frac{x ^{2} + 32 x}{8}

\int \frac{x ^{n}}{n ^{2}} d x

\int (x^{3} - 3 x) d x

\int_{2}^{5} e^{5 x} d x

x \to 1 lim (3 ln (x) + 4)

What is (\partial)/(\partial x)(((x-y))/((z-y))) ?
The answer to (\partial)/(\partial x)(((x-y))/((z-y))) is 1/(z-y)