What is (\partial)/(\partial x)(4xcos(xy)) ?

The answer to (\partial)/(\partial x)(4xcos(xy)) is 4(cos(xy)-xysin(xy))

Popular >

(\partial)/(\partial x)(4xcos(xy))

\frac{\partial}{\partial x} (4 x cos (x y))

4 (cos (x y) - x y sin (x y))

Solution steps

\frac{\partial}{\partial x} (4 x cos (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (x cos (x y))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = cos (x y)

= 4 (\frac{\partial}{\partial x} (x) cos (x y) + \frac{\partial}{\partial x} (cos (x y)) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (cos (x y)) = - sin (x y) y

= 4 (1 \cdot cos (x y) + (- sin (x y) y) x)

Simplify

= 4 (cos (x y) - x y sin (x y))

f (x) = x^{2} + x + 2, 0, 12

\int \frac{4 + 7 x}{1 + x ^{2}} d x

\frac{d}{d x} (6 x (x^{2} - 1)^{2})

\int_{0}^{1} \frac{1}{16 - x ^{2}} d x

\int \frac{4 x ln ( 1 + x ^{2} )}{1 + x ^{2}} d x

What is (\partial)/(\partial x)(4xcos(xy)) ?
The answer to (\partial)/(\partial x)(4xcos(xy)) is 4(cos(xy)-xysin(xy))