What is the solution for (dy)/(dx)+y/x = 3/y ?

The solution for (dy)/(dx)+y/x = 3/y is y=(sqrt(2x^3+c_{1)})/x ,y=-(sqrt(2x^3+c_{1)})/x

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(dy)/(dx)+y/x = 3/y

\frac{d y}{d x} + \frac{y}{x} = \frac{3}{y}

y = \frac{2 x ^{3} + c _{1}}{x}, y = - \frac{2 x ^{3} + c _{1}}{x}

Solution steps

\frac{d y}{d x} + \frac{y}{x} = \frac{3}{y}

Solve Bernoulli ODE:

y = \frac{2 x ^{3} + c _{1}}{x}, y = - \frac{2 x ^{3} + c _{1}}{x}

y = \frac{2 x ^{3} + c _{1}}{x}, y = - \frac{2 x ^{3} + c _{1}}{x}

\frac{d}{d x} (e^{x} (x - 2)^{2})

y = ln (a - 1)

\int \frac{x ^{2} + 6 x + 6}{x ^{3} + 9 x ^{2} + 18 x + 7} d x

\frac{d}{d x} (\frac{54}{( 3 x + 1 ) ^{4}})

x^{2} y^{^{'}} + 2 x y = 9 cos^{2} (x)

What is the solution for (dy)/(dx)+y/x = 3/y ?
The solution for (dy)/(dx)+y/x = 3/y is y=(sqrt(2x^3+c_{1)})/x ,y=-(sqrt(2x^3+c_{1)})/x