What is (\partial)/(\partial t)(x^2sin(3t)) ?

The answer to (\partial)/(\partial t)(x^2sin(3t)) is x^2cos(3t)*3

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(\partial)/(\partial t)(x^2sin(3t))

\frac{\partial}{\partial t} (x^{2} sin (3 t))

x^{2} cos (3 t) \cdot 3

Solution steps

\frac{\partial}{\partial t} (x^{2} sin (3 t))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} \frac{\partial}{\partial t} (sin (3 t))

Apply the chain rule:

cos (3 t) \frac{\partial}{\partial t} (3 t)

= cos (3 t) \frac{\partial}{\partial t} (3 t)

\frac{\partial}{\partial t} (3 t) = 3

= x^{2} cos (3 t) \cdot 3

\frac{d}{d x} (\frac{( x ^{2} - 1 )}{2 x - 3})

x \to 1 + lim (∣ x ∣)

x (2 x - 3)^{\frac{1}{2}}

y = \frac{3}{2}, y = \frac{1}{1 - x ^{2}}

ln (\frac{e ^{2 x} ( x ^{2} + 3 )}{x + 2})

What is (\partial)/(\partial t)(x^2sin(3t)) ?
The answer to (\partial)/(\partial t)(x^2sin(3t)) is x^2cos(3t)*3