What is the derivative of y=4\sqrt[5]{x^2}-3 ?

The derivative of y=4\sqrt[5]{x^2}-3 is (8x)/(5(x^2)^{4/5)}

What is the first derivative of y=4\sqrt[5]{x^2}-3 ?

The first derivative of y=4\sqrt[5]{x^2}-3 is (8x)/(5(x^2)^{4/5)}

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derivative of

\frac{8 x}{5 ( x ^{2} ) ^{\frac{4}{5}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (3) = 0

= \frac{8 x}{5 ( x ^{2} ) ^{\frac{4}{5}}} - 0

Simplify

= \frac{8 x}{5 ( x ^{2} ) ^{\frac{4}{5}}}

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What is the derivative of y=4\sqrt[5]{x^2}-3 ?
The derivative of y=4\sqrt[5]{x^2}-3 is (8x)/(5(x^2)^{4/5)}
What is the first derivative of y=4\sqrt[5]{x^2}-3 ?
The first derivative of y=4\sqrt[5]{x^2}-3 is (8x)/(5(x^2)^{4/5)}