What is the tangent of x^4-5x^2+4,\at x=1 ?

The tangent of x^4-5x^2+4,\at x=1 is y=-6x+6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of x^4-5x^2+4,\at x=1

tangent of

x^{4} - 5 x^{2} + 4, at x = 1

y = - 6 x + 6

Solution steps

Find the tangent point:

(1, 0)

Find the slope of

y = x^{4} - 5 x^{2} + 4 : \frac{d y}{d x} = 4 x^{3} - 10 x

Compute the slope of

y = x^{4} - 5 x^{2} + 4

x = 1 : m = - 6

Find the line with slope m=

- 6

and passing through

(1, 0) : y = - 6 x + 6

y = - 6 x + 6

\frac{d y}{d t} = 2 y - y^{2}

\int 1 - sin (2 x) d x

x, \frac{1}{18 x ^{2}}, \frac{x}{16}

\frac{d y}{d x} = 60 y x^{14}

\int \frac{40}{1 - cos ( 5 x )} d x

What is the tangent of x^4-5x^2+4,\at x=1 ?
The tangent of x^4-5x^2+4,\at x=1 is y=-6x+6