What is the derivative of tan(x-e^{-x}) ?

The derivative of tan(x-e^{-x}) is sec^2(x)+e^{-x}

What is the first derivative of tan(x-e^{-x}) ?

The first derivative of tan(x-e^{-x}) is sec^2(x)+e^{-x}

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\frac{d}{d x} (tan (x) - e^{- x})

sec^{2} (x) + e^{- x}

Solution steps

\frac{d}{d x} (tan (x) - e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (tan (x)) - \frac{d}{d x} (e^{- x})

\frac{d}{d x} (tan (x)) = sec^{2} (x)

\frac{d}{d x} (e^{- x}) = - e^{- x}

= sec^{2} (x) - (- e^{- x})

Simplify

= sec^{2} (x) + e^{- x}

\int_{0}^{1} e^{3 x + 1} d x

\frac{d}{d x} (\frac{( x ^{2} + 4 )}{x})

y = 2 x^{3} - 8 x, (2, 0)

\frac{d v}{d t} = - v

\int s h \frac{x}{3} d x

What is the derivative of tan(x-e^{-x}) ?
The derivative of tan(x-e^{-x}) is sec^2(x)+e^{-x}
What is the first derivative of tan(x-e^{-x}) ?
The first derivative of tan(x-e^{-x}) is sec^2(x)+e^{-x}