What is the tangent of f(x)=x-5sin(x),\at x= pi/2 ?

The tangent of f(x)=x-5sin(x),\at x= pi/2 is y=x-5

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tangent of f(x)=x-5sin(x),\at x= pi/2

tangent of

f (x) = x - 5 sin (x), at x = \frac{π}{2}

y = x - 5

Solution steps

Find the tangent point:

(\frac{π}{2}, \frac{π}{2} - 5)

Find the slope of

f (x) = x - 5 sin (x) : \frac{df ( x )}{d x} = 1 - 5 cos (x)

Compute the slope of

f (x) = x - 5 sin (x)

x = \frac{π}{2} : m = 1

Find the line with slope m=

1

and passing through

(\frac{π}{2}, \frac{π}{2} - 5) : y = x - 5

y = x - 5

x \to - 7 + lim (\frac{x + 6}{x + 7})

\int \frac{12}{x} d x

x \to 0 lim (\frac{1}{x})

\int \frac{x}{x ^{2} + 7} d x

x d y = (y + x^{2} + 9 y^{2}) d x

What is the tangent of f(x)=x-5sin(x),\at x= pi/2 ?
The tangent of f(x)=x-5sin(x),\at x= pi/2 is y=x-5