What is the derivative of (x^2-3x-54/(x+6)) ?

The derivative of (x^2-3x-54/(x+6)) is 1

What is the first derivative of (x^2-3x-54/(x+6)) ?

The first derivative of (x^2-3x-54/(x+6)) is 1

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\frac{d}{d x} (\frac{x ^{2} - 3 x - 54}{x + 6})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 3 x - 54}{x + 6})

Simplify

\frac{x ^{2} - 3 x - 54}{x + 6} : x - 9

= \frac{d}{d x} (x - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (9)

\frac{d x}{d x} = 1

\frac{d}{d x} (9) = 0

= 1 - 0

Simplify

= 1

f (x) = 5 - 2 x

y = x + 2, y = x^{2}, y = 0

\int sin^{2} (k x) d x

x \to - 7 - lim (\frac{1}{x ^{3} + 7 x ^{2}})

What is the derivative of (x^2-3x-54/(x+6)) ?
The derivative of (x^2-3x-54/(x+6)) is 1
What is the first derivative of (x^2-3x-54/(x+6)) ?
The first derivative of (x^2-3x-54/(x+6)) is 1