What is (\partial)/(\partial u(v))(u(v)^2e^{-v}) ?

The answer to (\partial)/(\partial u(v))(u(v)^2e^{-v}) is -e^{-v}v^2+2e^{-v}v

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(\partial)/(\partial u(v))(u(v)^2e^{-v})

\frac{\partial ^{2}}{\partial u ( v ) \partial v} (u (v) (v)^{2} e^{- v})

- e^{- v} v^{2} + 2 e^{- v} v

Solution steps

\frac{\partial ^{2}}{\partial u ( v ) \partial v} (u (v) (v)^{2} e^{- v})

\frac{\partial}{\partial u ( v )} (u (v) v^{2} e^{- v}) = e^{- v} v^{2}

= \frac{\partial}{\partial v} (e^{- v} v^{2})

\frac{\partial}{\partial v} (e^{- v} v^{2}) = - e^{- v} v^{2} + 2 e^{- v} v

= - e^{- v} v^{2} + 2 e^{- v} v

\frac{d}{d x} (5 - 4 x^{2})

e^{7 t}

\frac{d}{d x} (ln (x^{2} - 7 x + 1))

\int \frac{1}{9 x ^{2} + 12 x + 8} d x

f (x) = sin (2 x), \frac{π}{2}, π

What is (\partial)/(\partial u(v))(u(v)^2e^{-v}) ?
The answer to (\partial)/(\partial u(v))(u(v)^2e^{-v}) is -e^{-v}v^2+2e^{-v}v