What is the tangent of f(x)= 4/(3x-1),\at x=1 ?

The tangent of f(x)= 4/(3x-1),\at x=1 is y=-3x+5

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tangent of f(x)= 4/(3x-1),\at x=1

tangent of

f (x) = \frac{4}{3 x - 1}, at x = 1

y = - 3 x + 5

Solution steps

Find the tangent point:

(1, 2)

Find the slope of

f (x) = \frac{4}{3 x - 1} : \frac{df ( x )}{d x} = - \frac{12}{( 3 x - 1 ) ^{2}}

Compute the slope of

f (x) = \frac{4}{3 x - 1}

x = 1 : m = - 3

Find the line with slope m=

- 3

and passing through

(1, 2) : y = - 3 x + 5

y = - 3 x + 5

x (x + 1) \cdot \frac{d y}{d x} + x y = 1

f (x) = tan (x) \cdot cot (x)

\int \frac{8}{( x - 4 ) ^{2}} d x

sin (5 t - \frac{π}{3})

x \to \infty lim ((\frac{x}{x + 1})^{2 x})

What is the tangent of f(x)= 4/(3x-1),\at x=1 ?
The tangent of f(x)= 4/(3x-1),\at x=1 is y=-3x+5