What is the derivative of (-3/(x+1)) ?

The derivative of (-3/(x+1)) is 3/((x+1)^2)

What is the first derivative of (-3/(x+1)) ?

The first derivative of (-3/(x+1)) is 3/((x+1)^2)

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\frac{d}{d x} (\frac{- 3}{x + 1})

\frac{3}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{- 3}{x + 1})

Simplify

\frac{- 3}{x + 1} : - \frac{3}{x + 1}

= \frac{d}{d x} (- \frac{3}{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (\frac{1}{x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 3 \frac{d}{d x} ((x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

= - \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= - 3 (- \frac{1}{( x + 1 ) ^{2}} \cdot 1)

Simplify

- 3 (- \frac{1}{( x + 1 ) ^{2}} \cdot 1) : \frac{3}{( x + 1 ) ^{2}}

= \frac{3}{( x + 1 ) ^{2}}

n = 1 \sum \infty \frac{n ^{8}}{n !}

\frac{d}{d x} (x^{3} - x^{2} - 6 x)

\frac{d}{d x} ((x^{- 2} + x)^{3})

y^{^{''}} - 4 y^{^{'}} - 5 y = 0, y (1) = 0, y^{^{'}} (1) = 2

n = 1 \sum \infty 8^{n}

What is the derivative of (-3/(x+1)) ?
The derivative of (-3/(x+1)) is 3/((x+1)^2)
What is the first derivative of (-3/(x+1)) ?
The first derivative of (-3/(x+1)) is 3/((x+1)^2)