What is the derivative of g(x)=sqrt(9-x) ?

The derivative of g(x)=sqrt(9-x) is -1/(2sqrt(9-x))

What is the first derivative of g(x)=sqrt(9-x) ?

The first derivative of g(x)=sqrt(9-x) is -1/(2sqrt(9-x))

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derivative of

g (x) = 9 - x

- \frac{1}{2 9 - x}

Solution steps

\frac{d}{d x} (9 - x)

Apply the chain rule:

\frac{1}{2 9 - x} \frac{d}{d x} (9 - x)

= \frac{1}{2 9 - x} \frac{d}{d x} (9 - x)

\frac{d}{d x} (9 - x) = - 1

= \frac{1}{2 9 - x} (- 1)

Simplify

= - \frac{1}{2 9 - x}

\frac{d y}{d x} = \frac{2 y ^{2}}{x ^{2}}

\frac{d y}{d x} = \frac{10 x}{3 y}

\int x^{3} e^{- x} d x

\frac{d}{d x} (\frac{1}{ln ( x + 1 )} - \frac{1}{ln ( x + 3 )})

x \to 0 lim (x \cdot csc (x))

What is the derivative of g(x)=sqrt(9-x) ?
The derivative of g(x)=sqrt(9-x) is -1/(2sqrt(9-x))
What is the first derivative of g(x)=sqrt(9-x) ?
The first derivative of g(x)=sqrt(9-x) is -1/(2sqrt(9-x))