What is the derivative of x^4-3 ?

The derivative of x^4-3 is 4x^3

What is the first derivative of x^4-3 ?

The first derivative of x^4-3 is 4x^3

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\frac{d}{d x} (x^{4} - 3)

4 x^{3}

Solution steps

\frac{d}{d x} (x^{4} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (3) = 0

= 4 x^{3} - 0

Simplify

= 4 x^{3}

\frac{d y}{d x} = e^{- a \cdot x} - b \cdot y, y (0) = 0

\int \frac{( 2 r + 1 )}{r ^{2} - 3 r + 2} d r

x \to 10 lim (\frac{1}{( x - 10 ) ^{2}})

\frac{e ^{- 4 s}}{s ^{3}}

\int x 25 - x^{2} d x