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Popular >

3x+y-2+y^'(x-1)=0

Solution

3 x + y - 2 + y^{^{'}} (x - 1) = 0

Solution

y = - 3 x + 5 + \frac{c _{1}}{e ^{x}}

Solution steps

3 x + y - 2 + y^{'} (x) = 0

Solve linear ODE:

y = - 3 x + 5 + \frac{c _{1}}{e ^{x}}

y = - 3 x + 5 + \frac{c _{1}}{e ^{x}}

Popular Examples

integral from 1 to 2 of pi(2-1/2 x)^2

\int_{1}^{2} π (2 - \frac{1}{2} x)^{2} d x

tangent of x=fxx^3-4x,(-2,0)tangent of

x = f x x^{3} - 4 x, (- 2, 0)

limit as x approaches 10-of 9/(x-10)

x \to 10 - lim (\frac{9}{x - 10})

derivative of sqrt((7-x^2))

\frac{d}{d x} ((7 - x^{2}))

derivative of 1-x derivative of

1 - x

Frequently Asked Questions (FAQ)

What is the solution for 3x+y-2+y^'(x-1)=0 ?
The solution for 3x+y-2+y^'(x-1)=0 is y=-3x+5+(c_{1})/(e^x)