What is the tangent of f(x)= 3/x ,(-8,-3/8) ?

The tangent of f(x)= 3/x ,(-8,-3/8) is y=-3/64 x-3/4

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tangent of f(x)= 3/x ,(-8,-3/8)

tangent of

f (x) = \frac{3}{x}, (- 8, - \frac{3}{8})

y = - \frac{3}{64} x - \frac{3}{4}

Solution steps

Find the slope of

f (x) = \frac{3}{x} : \frac{df ( x )}{d x} = - \frac{3}{x ^{2}}

Compute the slope of

f (x) = \frac{3}{x}

(- 8, - \frac{3}{8}) : m = - \frac{3}{64}

Find the line with slope m=

- \frac{3}{64}

and passing through

(- 8, - \frac{3}{8}) : y = - \frac{3}{64} x - \frac{3}{4}

y = - \frac{3}{64} x - \frac{3}{4}

\frac{d}{d h} (\frac{e ^{ah} - 1}{h})

x \to 4 lim (x ∣ x - 4 ∣)

\int \frac{x ^{2} - x - 8}{( 2 x - 3 ) ( x ^{2} + 2 x + 2 )} d x

\int - \frac{7}{64 + 36 t ^{2}} d t

\frac{d}{d x} (\frac{2 + x}{1 - 2 x})

What is the tangent of f(x)= 3/x ,(-8,-3/8) ?
The tangent of f(x)= 3/x ,(-8,-3/8) is y=-3/64 x-3/4